yang611 发表于 2006-8-25 22:56:00

在arx中 如何获得角度值

<P>在arx中 如何直接获得角度值</P>
<P>（360度格式，非弧度数值）</P>
<P>比如 输入15 ，即角度为15度</P>

yang611 发表于 2006-8-28 15:28:00

<P>怎么没人能帮我？</P>

mjtppf 发表于 2006-8-28 15:43:00

<P>ARX有一个全局函数AcUtAngle（）；</P>
<P>原型及解释如下，在ARX的帮助中有：</P>
<P class=signature>ads_real</P>
<P class=signature>acutAngle(</P>
<P class=signatureIn>const ads_point pt1,</P>
<P class=signatureInEnd>const ads_point pt2);</P>
<P>
<TABLE class=argumentList>
<TBODY>
<TR vAlign=baseline>
<TD class=argumentName>pt1</TD>
<TD class=argumentDescription>Description to come</TD></TR>
<TR vAlign=baseline>
<TD class=argumentName>pt2</TD>
<TD class=argumentDescription>Description to come</TD></TR></TBODY></TABLE></P>
<P>Finds the angle between a line and the current X axis.</P>
<P>Returns the angle of the line defined by pt1 and pt2. The acutAngle() function measures the angle from the X axis of the current User Coordinate System (UCS), with the angle increasing in the counterclockwise direction. It returns the value in radians. This function treats pt1 and pt2 as two-dimensional points; it ignores their Z coordinates, in effect projecting the line onto the current construction plane.</P>
<P>不过返回的是弧度值，需要转换为角度值。</P>

mjtppf 发表于 2006-8-28 15:44:00

不好意思，函数名写错了，是acutAngle，不是AcUtAngle

yang611 发表于 2006-8-29 16:55:00

<P>您好像没看懂我的意思</P>
<P>应该是这样</P>
<P>从键盘输入 15 给参数 angle</P>
<P>则angle＝15度，</P>
<P>就像输入ads_real 一样的</P>
<P>&nbsp;</P>
<P>&nbsp;</P>

nc2t 发表于 2006-8-30 10:44:00

<P>好象不能直接做，但是你可以从程序里，将弧度值修改为角度值，然后赋　给一个变量，很简单的</P>
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