[求助]求两条曲线的交点
<P><FONT face=宋体 size=2>ARX求两条曲线的交点有什么方法，用到哪些类？请帮忙，谢谢！</FONT></P><P><FONT face=宋体 size=2></FONT><FONT face=宋体 size=2><BR>另，高手提示一下“拷贝”，旋转，镜像，剪切等要用到哪些函数，用到哪些类？</P>
<P>给点提示吧，高手不要一来就让看帮助。没有眉目，不知道从哪里下手。期待中......</FONT></P> <P>买本计算机图形学看看，或者在网上找找</P> <P>virtual Acad::ErrorStatus</P>
<P>AcDbEntity::intersectWith(</P>
<P>const AcDbEntity* pEnt,</P>
<P>AcDb::Intersect intType,</P>
<P>AcGePoint3dArray& points,</P>
<P>int thisGsMarker = 0,</P>
<P>int otherGsMarker = 0) const;</P>
<P>pEnt Input entity with which "this" entity is to intersect </P>
<P>intType Input type of intersection requested </P>
<P>points Output with the points of intersection appended </P>
<P>thisGsMarker Input GS marker of subentity of "this" entity that's involved in the intersection operation. Use the 0 default if not applicable. </P>
<P>otherGsMarker Input GS marker of subentity of the entity pointed to by pEnt that's involved in the intersection operation. Use the 0 default if not applicable.</P>
<P>使用这个函数可以求得任意两个图元的所有交点。详情见SDK文档</P>
<P>拷贝，镜像使用getTransformedCopy():</P>
<P class=signature>virtual Acad::ErrorStatus<BR>getTransformedCopy(<BR>const AcGeMatrix3d& xform,<BR>AcDbEntity*& pEnt) const;</P>
<P class=signature>xform是这个图元的变化矩阵，详情见SDK文档AcGeMatrix3d条目</P>
<P class=signature>第二个参数是一个指针，在你使用这个函数的时候，必须给它一个空的指针变量，它将地址返回给你的变量:</P>
<P class=signature><FONT size=2>旋转使用AcDbEntity::transformBy函数：</P>
<P class=signature>virtual Acad::ErrorStatus<BR>transformBy(<BR>const AcGeMatrix3d& xform);<BR></P>
<P class=signature>xform是变换矩阵</P>
<P class=signature>剪切只能使用trim命令</P></FONT>
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