Andyhon 发表于 2007-6-17 10:32:00

<p></p><p>作图略述<br/>粗估后用24边形起始半径<br/>先用内接圆心做为新圆的圆心<br/>再用直线与100的圆周交点做为新圆的圆心<br/>再用之前各圆心串出圆弧轨迹线....</p><p>用最后三个圆心串出圆弧 ... 直到所要的精度</p><p></p>

Joseflin 发表于 2007-6-17 12:46:00

<p><strong><font face="Verdana" color="#61b713">Andyhon的構想很有創意,以24邊形做作好像有誤差,請再思考一下。</font></strong></p><p><strong><font face="Verdana" color="#61b713">答案為a=26.4491</font></strong></p>

Joseflin 发表于 2007-6-17 16:41:00

<p>我以Andyhon的方法作出來表面上似乎沒問題但答案卻有差距,不知錯誤出在那兒故貼出來請大家幫我check check。</p><p>&nbsp;</p><div style="WIDTH: 728px; HEIGHT: 90px;"><script type="text/javascript"></script><script src="http://pagead2.googlesyndication.com/pagead/show_ads.js" type="text/javascript"></script><iframe name="google_ads_frame" marginwidth="0" marginheight="0" src="http://pagead2.googlesyndication.com/pagead/ads?client=ca-pub-7471407183047897&amp;dt=1182069257419&amp;lmt=1182069257&amp;prev_fmts=728x90_as%2C120x90_0ads_al_s&amp;format=728x90_as&amp;output=html&amp;correlator=1182069257169&amp;channel=9653521252&amp;pv_ch=9653521252%2B&amp;url=http%3A%2F%2Fwww.mjtd.com%2Fbbs%2Fdispbbs.asp%3Fboardid%3D37%26replyid%3D61314%26id%3D60977%26page%3D1%26skin%3D0%26Star%3D2&amp;color_bg=FFFFFF&amp;color_text=000000&amp;color_link=0000FF&amp;color_url=008000&amp;color_border=C3D9FF&amp;ad_type=text_image&amp;ref=http%3A%2F%2Fwww.mjtd.com%2Fbbs%2Fdispbbs.asp%3FboardID%3D37%26ID%3D60977%26page%3D1&amp;cc=100&amp;flash=9&amp;u_h=864&amp;u_w=1152&amp;u_ah=830&amp;u_aw=1152&amp;u_cd=32&amp;u_tz=480&amp;u_his=9&amp;u_java=true" frameborder="0" width="728" scrolling="no" height="90" allowtransparency="allowtransparency"></iframe></div><p><strong><font face="Verdana" color="#61b713">Andyhon</font></strong></p>

Lotto168 发表于 2007-6-20 14:11:00

Joseflin 发表于 2007-6-21 08:21:00

<p><strong><font face="Verdana" color="#61b713">Lotto168可否說明作法?</font></strong></p>
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