zxmmelly 发表于 2008-5-23 19:18:00

[原创]表的交集 并集 差集

本帖最后由 作者 于 2008-5-23 19:18:26 编辑 <br /><br /> ;;--求两个表的交集---------------------------------------------------<br/>&nbsp; (defun lst-union (<a href="mailto:#@lst1">#@lst1</a><br/>&nbsp;<a href="mailto:#@lst2">#@lst2</a> / $lst2 #lst2)<br/>&nbsp;&nbsp;&nbsp; (setq $lst2&nbsp;(append <a href="mailto:#@lst1">#@lst1</a><br/>&nbsp;<a href="mailto:#@lst2">#@lst2</a>)<br/>&nbsp;&nbsp; #lst2&nbsp;(lst-intersect <a href="mailto:#@lst1">#@lst1</a><br/>&nbsp;<a href="mailto:#@lst2">#@lst2</a>)<br/>&nbsp;&nbsp;&nbsp; )<br/>&nbsp;&nbsp;&nbsp; (if&nbsp;#lst2<br/>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; (setq $lst2<br/>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; (append (foreach x #lst2 (setq $lst2 (vl-remove x $lst2)))<br/>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; #lst2<br/>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; )<br/>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; )<br/>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; $lst2<br/>&nbsp;&nbsp;&nbsp; )<br/>&nbsp; )<br/>;;--求两个表的差集---------------------------------------------------<br/>&nbsp; (defun lst-subtract (<a href="mailto:#@lst1">#@lst1</a><br/>&nbsp;<a href="mailto:#@lst2">#@lst2</a> /)<br/>&nbsp;&nbsp;&nbsp; (if&nbsp;(setq #lst2 (lst-intersect <a href="mailto:#@lst1">#@lst1</a><br/>&nbsp;<a href="mailto:#@lst2">#@lst2</a>))<br/>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; (foreach x #lst2 (setq <a href="mailto:#@lst1">#@lst1</a> (vl-remove x <a href="mailto:#@lst1">#@lst1</a>)))<br/>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; <a href="mailto:#@lst1">#@lst1</a><br/>&nbsp;&nbsp;&nbsp; )<br/>&nbsp; )<br/>;;--求两个表的交集---------------------------------------------------<br/>&nbsp; (defun lst-intersect (<a href="mailto:#@lst1">#@lst1</a><br/>&nbsp;<a href="mailto:#@lst2">#@lst2</a> / nn @z @lst2)<br/>&nbsp;&nbsp;&nbsp; (setq nn 0)<br/>&nbsp;&nbsp;&nbsp; (while (setq @z (nth nn <a href="mailto:#@lst1">#@lst1</a>))<br/>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; (if (member @z <a href="mailto:#@lst2">#@lst2</a>)<br/>&nbsp;(setq @lst2 (cons @z @lst2))<br/>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; )<br/>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; (setq nn (1+ nn))<br/>&nbsp;&nbsp;&nbsp; )<br/>&nbsp;&nbsp;&nbsp; (if&nbsp;@lst2<br/>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; (reverse @lst2)<br/>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp; nil<br/>&nbsp;&nbsp;&nbsp; )<br/>&nbsp; )

caoyin 发表于 2008-5-25 10:03:00

(defun lst-union (lst1 lst2)<br/>&nbsp; (append lst1 (vl-remove-if '(lambda (x) (member x lst1)) lst2))<br/>)<br/>(defun lst-subtract (lst1 lst2 / lst)<br/>&nbsp; (setq lst (append lst1 lst2))<br/>&nbsp; (vl-remove-if '(lambda (x) (member x (cdr (member x lst)))) lst)<br/>)<br/>(defun lst-intersect (lst1 lst2)<br/>&nbsp; (vl-remove-if-not '(lambda (x) (member x lst2)) lst1)<br/>)

vlisp2012 发表于 2012-11-29 19:55:38

学习了，做个记号！

yjtdkj 发表于 2021-7-20 16:56:24

本帖最后由 yjtdkj 于 2021-7-20 17:10 编辑

caoyin 发表于 2008-5-25 10:03
(defun lst-union (lst1 lst2)(append lst1 (vl-remove-if '(lambda (x) (member x lst1)) lst2)))( ...
你这个差集不对，这个不叫差集，应该是两集合去掉交集后剩下的部分，也就是对称差Symmetric Difference

tryhi 发表于 2021-7-20 17:51:51

yjtdkj 发表于 2021-7-20 16:56
你这个差集不对，这个不叫差集，应该是两集合去掉交集后剩下的部分，也就是对称差Symmetric Difference

好像叫交集取反？

paulpipi 发表于 2021-8-3 23:21:10

好东西，收藏备用，谢谢！
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