[求助]帮忙调试一下代码
<p>;;代码如下,此段代码怎么没有实现把 pt1 pt2 赋给pts;即pts中只含有pt3 与pt4的表?</p><p>;;我想实现pts如样图的输出方式;见附件</p><p>(defun c:tt( / pts<br/> pt1<br/> pt2<br/> pt3<br/> pt4)<br/>(setq pt1(getpoint"<a href="file://nInput/">\\nInput</a> first point:"))<br/>(setq pt2(getpoint"<a href="file://nInput/">\\nInput</a> send point:"))<br/>(setq pt3(getpoint"<a href="file://nInput/">\\nInput</a> thd point:"))<br/>(setq pt4(getpoint"<a href="file://nInput/">\\nInput</a> foth point:"))<br/>(setq pts (list pt1 pt2))<br/>(setq pts (append pts(list pt3 pt4))))<br/> </p><p> </p> <p>(defun c:tt( / pts pt1 pt2 pt3 pt4)<br/> (setq pt1 (getpoint"<a href="file://\\nInput">\nInput</a> first point:"))<br/> (setq pt2 (getpoint"<a href="file://\\nInput">\nInput</a> send point:"))<br/> (setq pt3 (getpoint"<a href="file://\\nInput">\nInput</a> thd point:"))<br/> (setq pt4 (getpoint"<a href="file://\\nInput">\nInput</a> foth point:"))<br/> (setq pts (list(list pt1 pt2)))<br/> (setq pts (append pts (list(list pt3 pt4))))<br/>)<br/></p> 谢谢!可以的
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