请问，若已知一条线的坐标，如何删除这条线呢？

saintlzh

用什么函数呢？

wxj351

[此贴子已经被wxj351于2003-3-15 0:18:38编辑过]

JicketMoney

假设直线的坐标：起点pt1,端点pt2;
struct resbuf rb;
ads_name ss;
rb.restype = 0;
char sbuf[10];
strcpy (sbuf, "LINE");
rb.resval.rstring = sbuf;
rb.rbnext = NULL;
if (acedSSGet("C", asDblArray(pt1), asDblArray(pt2), &rb, ss) == RTNORM)
{
long len;
ads_name ent;
AcDbObjectId objId;
acedSSLength(ss, &len);
for (int i=0; i<len; i++)
{
acedSSName(ss, i, ent);
acedGetObjectId(objId, ent);
AcDbLine *pLine = NULL;
acdbOpenObject(pLine, objId, AcDb::kForRead);
if (pLine != NULL)
{
if (pLine->startPoint() == pt1 && pLine->endPoint() == pt2)
pLine->erase();
pLine->close();
}
}
acedSSFree(ss);
}
未经调试，仅供参考

saintlzh

[此贴子已经被作者于2003-3-17 10:12:41编辑过]

zfbj