请各位帮忙

yang611

提示 用户选择两个点，将两点联成直线

为何不能实现啊 ，代码如下：

ads_point startPt, endPt;

 acedGetPoint(NULL,"\nLocate start point : ", startPt);

 acedGetPoint(NULL,"\nLocate end point : ", endPt);

  AcDbLine *pLine = new AcDbLine(startPt,endPt);

//error C2664: '__thiscall AcDbLine::AcDbLine(const class AcGePoint3d &,const class AcGePoint3d &)' : cannot convert parameter 1 from 'double [3]' to 'const class AcGePoint3d &'
        Reason: cannot convert from 'double [3]' to 'const class AcGePoint3d'
        No constructor could take the source type, or constructor overload resolution was ambiguous

请各位帮忙指点一二

shinjikun

第一点，AcDbLine接受的不是ads_point而是AcGePoint3d,要把ads_point 转换为AcGePoint3d，可以这样写：

(假定 ads_point s;AcGePoint3d p;)

p.set(s[0],s[1],s[2]);

但是你得程序可以有更快的写法：

AcDbLine *pLine = new AcDbLine(*(AcGePoint3d*)startPt,*(AcGePoint3d*)endPt);

第二点，你必须把你的图元加入到数据库中才行，这个可以参考SDK上的写法：

 AcDbBlockTable *pBlockTable;
  acdbHostApplicationServices()->workingDatabase()
   ->getSymbolTable(pBlockTable, AcDb::kForRead);

  AcDbBlockTableRecord *pBlockTableRecord;
  pBlockTable->getAt(ACDB_MODEL_SPACE, pBlockTableRecord,
   AcDb::kForWrite);
  pBlockTable->close();

  AcDbObjectId lineId;
  pBlockTableRecord->appendAcDbEntity(lineId, pLine);

  pBlockTableRecord->close();
  pLine->close();