菜鸟求助!折腾了我一下午的问题

coldmoon

以下是我所编写的一段代码,目的是将2条重合的线合并成一条.编译可以通过,但在CAD上运行老是出错.本菜鸟对ARX 实在不熟,对此问题也是实在没折了,万望各位大侠,不吝赐教.

// ObjectARX defined commands

#include "StdAfx.h"
#include "StdArx.h"

#include "myline.h"

AcGePoint3d get_startpoint,get_endpoint;

AcGePoint3d judgement(Cmyline Cmyline1,Cmyline Cmyline2);

// This is command 'REPLINE'
void zzh_hfutrepline()
{
 // TODO: Implement the command
    AcDbBlockTable *pBT;
 acdbHostApplicationServices()->workingDatabase()->getSymbolTable(pBT,AcDb::kForRead);//取出当前数据库的实体表
  
 AcDbBlockTableIterator* pIterator;
 pBT->newIterator(pIterator);
 pBT->close();

AcDbLine *pLine[20],*pLine1; 
Cmyline myline1[20];                 //自己定义的直线类，用于存储各个直线的端点
 

  int i=0,Count=0;

 for (pIterator->start();!pIterator->done();pIterator->step())
 {
  AcDbBlockTableRecord *pBTR;
  pIterator->getRecord(pBTR,AcDb::kForRead,Adesk::kFalse);

  AcDbBlockTableRecordIterator* pIrterator;
  pBTR->newIterator(pIrterator);          //建立迭代器  
  pBTR->close();

   while(!pIrterator->done())
  {
   AcDbEntity*pEnt;
   pIrterator->getEntity(pEnt,AcDb::kForWrite); //打开实体，进行编辑
   if (pEnt->isA() == AcDbLine::desc())//若是线形，则继续
   {
    pLine=AcDbLine::cast(pEnt);
    
    myline1.startpt=pLine->startPoint();//将直线的两端点加以保存
    myline1.endpt=pLine->endPoint();
    

    pIrterator->step();
    i++;
    Count++;
   }
  }
  }
  delete pIrterator;
 }

 for (i=0; i<Count;i++)
  {
   for (int j=i+1;j<Count;j++)
   {
    judgement(myline1,myline1[j]);
    
    acdbHostApplicationServices()->workingDatabase()
       ->getSymbolTable(pBT,AcDb::kForWrite);
   
             pBT->getAt(ACDB_MODEL_SPACE, pBTR,AcDb::kForWrite);

    delete pLine;//删除图上的重复的线(这里错的吧 我不知道怎么删除线 相关资料没找到)
    delete pLine[j];

    pLine1=new AcDbLine(get_startpoint,get_endpoint);//重画一条线代替重复的两条线
    pLine1->close();
    
   }
  }
  
  for (i=0;i<Count;i++)
  {
   pLine->close();
   delete pIterator;
}

AcGePoint3d judgement(Cmyline Cmyline1,Cmyline Cmyline2)
{
 double fslope1,fslope2;//斜率
 double Sx1,Sy1,Ex1,Ey1;//比较时用到的第一条直线的两个端点坐标变量
 double Sx2,Sy2,Ex2,Ey2;//第二条直线端点坐标变量

 Sx1=Cmyline1.startpt.x;
 Sy1=Cmyline1.startpt.y;
 Ex1=Cmyline1.endpt.x;
 Ey1=Cmyline1.endpt.y;

 Sx2=Cmyline2.startpt.x;
 Sy2=Cmyline2.startpt.y;
 Ex2=Cmyline2.endpt.x;
 Ey2=Cmyline2.endpt.y;

 fslope1=(Ey1 - Sy1) / (Ex1 - Sx1);
 fslope2=(Ey2 - Sy2) / (Ex2 - Sx2);

 double Max_distance,distance1,distance2,distance3,distance4;

 distance1 = (Sx1 - Ex1) * (Sx1 - Ex1) + (Sy1 - Ey1) * (Sy1 - Ey1);//第一条直线两端点间的距离
 distance2 = (Sx2 - Ex2) * (Sx2 - Ex2) + (Sy2 - Ey2) * (Sy2 - Ey2);//第二条直线两端点间的距离
 distance3 = (Sx1 - Ex2) * (Sx1 - Ex2) + (Sy1 - Ey2) * (Sy1 - Ey2);//第一条直线起点于第二条直线终点间的距离
 distance4 = (Sx2 - Ex1) * (Sx2 - Ex1) + (Sy2 - Ey1) * (Sy2 - Ey1);//第一条直线终点与第二条直线起点间的距离

 if ((fslope1==fslope2)
  &&((Sy2==(Sx2-Sx1)*fslope1+Sy1)||(Ey2=(Ex2-Sx1)*fslope1+Sy1))
  &&((Sx1<=Sx2&&Sx2<=Ex1)||(Sx1<=Ex2&&Ex2<=Ex1))) {
  Max_distance=distance1;
  if (distance2>Max_distance)
   Max_distance=distance2;
  if (distance3>Max_distance)
   Max_distance=distance3;
  if (distance4>Max_distance)
   Max_distance=distance4;
  
     if (Max_distance==distance1)
  { get_startpoint.x=Sx1;
   get_startpoint.y=Sy1;
   get_endpoint.x=Ex1;
   get_endpoint.y=Ey1;
  }
   
     else if (Max_distance==distance2)
  {
   get_startpoint.x=Sx2;
      get_startpoint.y=Sy2;
   get_endpoint.x=Ex2;
   get_endpoint.y=Ey2;
  }
  else if (Max_distance==distance3)
  {
   get_startpoint.x=Sx1;
   get_startpoint.y=Sy1;
   get_endpoint.x=Ex2;
   get_endpoint.y=Ey2;
  }
  else if (Max_distance==distance4)
  {
   get_startpoint.x=Sx2;
   get_startpoint.y=Sy2;
   get_endpoint.x=Ex1;
  get_endpoint.y=Ey1;

  }
  else
  {
   ads_printf("\n error please restart the program !");
  
  }
 }
 return get_endpoint,get_startpoint;(是不是可以返回两个值,我不太清楚)
 
}

zhang007

myline1.startpt=pLine->startPoint();//将直线的两端点加以保存
    myline1.endpt=pLine->endPoint();

 pEnt->erase();
 pEnt->close();

zhang007

其实不用这么复杂,记住一条线的端点坐标后,再用后来的线端点逐一与它比较,如果相差不大就删掉后面的线.打开实体时一定要试试是不是能以写打开,否则CAD就崩了

好像用选择集更好

coldmoon

问题已经解决 结贴