我写了一个,但是不好。。
;;2010.05.29 ;;求直线长度并标记 ;;需选择直线、文字高度、比例因子
(DEFUN C:CD() (SETVAR "CMDECHO" 0) (GRAPHSCR) (SETQ K T) (WHILE K (INITGET "S L A") (SETQ K(GETKWORD "\n请选择直线[多条(S)][图层(L)/所有(A)]<退出>:")) (COND ((EQUAL K NIL)(EXIT)) ((EQUAL K "S")(SETQ E1 (SSGET))) ((EQUAL K "L")(INITGET 1)(SETQ layer_name (GETSTRING "\n请输入图层名:")) (SETQ E1 (SSGET "x" '((8 . "layer_name")(0 . "LINE"))))) ((EQUAL K "A")(SETQ E1(SSGET "X" '((0 . "LINE"))))) ) ;;;输入高度和比例因子 (SETQ H 10) (SETQ B 100) (INITGET 6) (SETQ H (GETDIST "\n请输入高度<10>:")) (SETQ B (GETREAL "\n请输入比例因子<100>: ")) ;:::::::::::::::: (SETQ SLEN (SSLENGTH E1)) (SETQ n 0) (WHILE (< n SLEN) (SETQ LL (SSNAME E1 n)) (SETQ ST (entget LL)) (SETQ P1 (CDR (ASSOC 10 ST))) ;获得直线起点坐标 (SETQ P2 (CDR (ASSOC 11 ST))) ;获得直线终点坐标 (SETQ ANG (ANGLE P1 P2)) ;获得直线角度 ;=== 求文字方向 (COND ((AND(< ANG (/ PI 2))(>= ANG 0)) (SETQ ANG1 ANG)) ((AND (>= ANG (/ PI 2))(< ANG PI))(SETQ ANG1 (+ ANG PI))) ((AND (>= ANG PI)(< ANG (* 1.5 PI))(SETQ ANG1 (- ANG PI)))) ((AND(>= ANG (* PI 1.5))(<= ANG (* 2 PI))) (SETQ ANG1 ANG)) ) ;.................... ;===求文字相对于直线位置 (COND ((AND(< ANG (/ PI 2))(>= ANG 0)) (SETQ ANG2 (+ ANG (* 0.5 PI)))) ((AND (>= ANG (/ PI 2))(<= ANG (* 1.5 PI))(SETQ ANG2 (- ANG (* 0.5 PI))))) ((AND(>= ANG (* PI 1.5))(<= ANG (* 2 PI))) (SETQ ANG2 (- ANG(* 1.5 PI)))) ) ;..................... (SETQ L (DISTANCE P1 P2)) ;获得直线长度 (SETQ L (FIX (+ L 0.5))) ;长度四舍五入后取整 (SETQ L (ITOA L)) ;将整数转换为字符串 (SETQ P3 (LIST(+ (CAR P1)(/(-(CAR P2)(CAR P1))2.0))(+(CADR P1)(/(-(CADR P2)(CADR P1))2.0)))) ;求直线中点 (SETQ P4 (POLAR P3 ANG2 (* H 0.8))) ;求文字中心点坐标 (SETQ ANG1 (/ (* ANG1 180) PI)) ;将弧度转化为角度 (SETQ TEX (STRCAT "L=" L)) ;连接字符串 (COMMAND ".TEXT" "J" "MC" P4 H ANG1 TEX) ;输出长度 (SETQ n (+ n 1)) ) ) )
求高手帮个忙。 |